This may well seem too simple but how would i work out the probability of rolling a "4" and then a "6". using P(4 or 6)=P(4) + P(6). Using this i came to the answer of 2/6 but that would mean that the probability is now greater than rolling just one 4 or 6. or am i confusing myself? shouldn't i be multiplying 1/6 * 1/6 or is that something else?
P(4 or 6) is not equal to P(4) -> P(6) (as in rolling one then the other) P(4 or 6) would be the probability of rolling either a 4 or a 6 given only one roll.
yes but how so? can you please analyse this formula for me?
p(a or b)= p(A) + p(B)
why is this a plus and not a multiplication symbol? i'm very confused.
the "+" is what's confusing me.
Take this example, On a fair dice, you have 6 possible outcomes. If you throw the dice, what is the probability that you'll land on either a 1 or 2 or 3 or 4 or 5 or 6?
Take this example, On a fair dice, you have 6 possible outcomes. If you throw the dice, what is the probability that you'll land on either a 1 or 2 or 3 or 4 or 5 or 6?
Okay, so you know that the probability of each outcome is 1/6, and the total probability adds up to 1. You also know that there are 6 possible outcomes. Everytime you roll a dice you get one of those outcomes (you get a 1 OR you get a 2 OR a 3 OR 4 OR 5 OR 6). 1/6 + 1/6 + 1/6 +... = 1 so P(1 OR 2 OR 3 OR 4 OR 5 OR 6) =1 Does this answer your question ?
Okay, so you know that the probability of each outcome is 1/6, and the total probability adds up to 1. You also know that there are 6 possible outcomes. Everytime you roll a dice you get one of those outcomes (you get a 1 OR you get a 2 OR a 3 OR 4 OR 5 OR 6). 1/6 + 1/6 + 1/6 +... = 1 so P(1 OR 2 OR 3 OR 4 OR 5 OR 6) =1 Does this answer your question ?