electron acceleration
It's a one mark MC question from OCR Oct 2020.
Can't figure out how the correct answer is apparently 1.1x10^7 m/s
An electron with initial kinetic energy of 100 eV and initial speed of 5.9 × 10^6 m/s is accelerated through a potential difference of 250 V. What is the final speed of this electron?
Of course eV=1/2mv^2 and 100eV does result in 5.9 × 10^6 m/s so they seem to have given excess information.
For 1 mark what am I missing?
The difference from the usual scenario is that the electron is not stationary.
Can't figure out how the correct answer is apparently 1.1x10^7 m/s
An electron with initial kinetic energy of 100 eV and initial speed of 5.9 × 10^6 m/s is accelerated through a potential difference of 250 V. What is the final speed of this electron?
Of course eV=1/2mv^2 and 100eV does result in 5.9 × 10^6 m/s so they seem to have given excess information.
For 1 mark what am I missing?
The difference from the usual scenario is that the electron is not stationary.
Original post by xlaser31
It's a one mark MC question from OCR Oct 2020.
Can't figure out how the correct answer is apparently 1.1x10^7 m/s
An electron with initial kinetic energy of 100 eV and initial speed of 5.9 × 10^6 m/s is accelerated through a potential difference of 250 V. What is the final speed of this electron?
Of course eV=1/2mv^2 and 100eV does result in 5.9 × 10^6 m/s so they seem to have given excess information.
For 1 mark what am I missing?
The difference from the usual scenario is that the electron is not stationary.
Can't figure out how the correct answer is apparently 1.1x10^7 m/s
An electron with initial kinetic energy of 100 eV and initial speed of 5.9 × 10^6 m/s is accelerated through a potential difference of 250 V. What is the final speed of this electron?
Of course eV=1/2mv^2 and 100eV does result in 5.9 × 10^6 m/s so they seem to have given excess information.
For 1 mark what am I missing?
The difference from the usual scenario is that the electron is not stationary.
Yeah, I'm not sure how the initial speed is helpful. It's easy to work out the new KE of the electron in eV, and then to find out its speed. All assuming that the acceleration is in the same direction as its initial motion. Is there some quick proportionality argument I'm missing?
Original post by xlaser31
It's a one mark MC question from OCR Oct 2020.
Can't figure out how the correct answer is apparently 1.1x10^7 m/s
An electron with initial kinetic energy of 100 eV and initial speed of 5.9 × 10^6 m/s is accelerated through a potential difference of 250 V. What is the final speed of this electron?
Of course eV=1/2mv^2 and 100eV does result in 5.9 × 10^6 m/s so they seem to have given excess information.
For 1 mark what am I missing?
The difference from the usual scenario is that the electron is not stationary.
Can't figure out how the correct answer is apparently 1.1x10^7 m/s
An electron with initial kinetic energy of 100 eV and initial speed of 5.9 × 10^6 m/s is accelerated through a potential difference of 250 V. What is the final speed of this electron?
Of course eV=1/2mv^2 and 100eV does result in 5.9 × 10^6 m/s so they seem to have given excess information.
For 1 mark what am I missing?
The difference from the usual scenario is that the electron is not stationary.
As Pangol hinted at, you would use a proportionality argument.
Velocity squared is proportional to the kinetic energy of the particle.
Kinetic energy increases to 350eV. Therefore,
Rearranging, and just substitute the values into your calculator to find it.
(edited 2 years ago)
Original post by Kyaurix
why does the kinetic energy increase to 350 bro?
E = QV, when you sub in you get E = 250 which is the change in kinetic energy, so final kinetic energy = 250 + 100 = 350.
GGG
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