A particle P moves from point A to point B with constant acceleration

(ci + dj) ms^2, where c and d are positive constants. The velocity of P at A is (-3i - 3j) ms and the velocity of P at B is (2i + 9j m s'. The magnitude of the acceleration of P is 2.6 ms^2.

Find the value of c and the value of d.

(ci + dj) ms^2, where c and d are positive constants. The velocity of P at A is (-3i - 3j) ms and the velocity of P at B is (2i + 9j m s'. The magnitude of the acceleration of P is 2.6 ms^2.

Find the value of c and the value of d.

Original post by banana_22xx

A particle P moves from point A to point B with constant acceleration

(ci + dj) ms^2, where c and d are positive constants. The velocity of P at A is (-3i - 3j) ms and the velocity of P at B is (2i + 9j m s'. The magnitude of the acceleration of P is 2.6 ms^2.

Find the value of c and the value of d.

(ci + dj) ms^2, where c and d are positive constants. The velocity of P at A is (-3i - 3j) ms and the velocity of P at B is (2i + 9j m s'. The magnitude of the acceleration of P is 2.6 ms^2.

Find the value of c and the value of d.

As per TSR policies, I cannot give you a direct answer. All I can do is drop hints.

•

Acceleration = speed/time

•

Acceleration is constant, so no differentiation is required and velocity is linear

•

Velocity graphs are different to acceleration graphs

•

Magnitude implies square roots

Original post by MindMax2000

As per TSR policies, I cannot give you a direct answer. All I can do is drop hints.

•

Acceleration = speed/time

Acceleration is not speed/time. Acceleration is $\dfrac{\text{change in velocity}}{\text{time}}$.

To the OP: what is it in the question you don't understand? [Note: if you don't understand how to answer the question, that is something different from not understanding the question. If so, just say so, it's fine, but at the moment we don't know what your problem actually is].

(edited 5 months ago)

Original post by MindMax2000

As per TSR policies, I cannot give you a direct answer. All I can do is drop hints.

•

Acceleration = speed/time

•

Acceleration is constant, so no differentiation is required and velocity is linear

•

Velocity graphs are different to acceleration graphs

•

Magnitude implies square roots

So how would I work out this question? I still don’t quite understand

Original post by banana_22xx

So how would I work out this question? I still don’t quite understand

Hint: Let T be the time it takes to get from A to B. Find the acceleration in terms of T.

Then use the given magnitude of the acceleration to find what T is.

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