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    This thread contains the many tribulations of a TSR user
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    you differentiate it, then put your answer equal to zero. Also this is on the normal IGCSE syllabus, cos i have my exam tomorrow and it is one of the topics i am revision
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    (Original post by M_E_X)
    The minimum point will be when x = -4. You have to set the inside of the bracket to zero.

    Sub x= -4 in to the original equation to find the value of the function at this point.

    source: http://www.mathcentre.ac.uk/resource...ingsquare1.pdf (section 4)
    The minimum point is at x = 4 not x = -4 though.
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    (Original post by jonny23563)
    Differentiate, set this equal to 0 to find stationary points.

    Check values either side of any stationary points to see whether they are minimum or maximum
    There's no need to check. A quadratic graph has the shape of a parabola, and if the coefficient of x^2 is positive, it will only have one minimum point and no other stationary points.
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    (Original post by Dingooose)
    There's no need to check. A quadratic graph has the shape of a parabola, and if the coefficient of x^2 is positive, it will only have one minimum point and no other stationary points.
    I think you'll find plenty of new threads to reply to.

    There's no need to resurrect a 6 year old thread
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    (Original post by notnek)
    I think you'll find plenty of new threads to reply to.

    There's no need to resurrect a 6 year old thread
    Whoops, my bad.
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    Double necro! It got revived once more in 2012, he's just keeping the 3-year cycle going
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    its as level
 
 
 
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