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    At 2pm the coastguard spots a dinghy 500m due south of his observation point. The dingy has constant velocity (2i + 3j)ms^-1.

    a) Find in terms of t, the position vector of the dinghy t seconds after 2 seconds.
    b) Find the distance of the dinghy from the observation point at 2:05pm

    I can do a) however im struggling with b) ................. i'll quickly run through a) so it will help with answer b)

    a) -500j + (2i + 3j)t = 2ti + (3t-500)j

    help with b) would be much appreciated
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    (Original post by Byrney11)
    At 2pm the coastguard spots a dinghy 500m due south of his observation point. The dingy has constant velocity (2i + 3j)ms^-1.

    a) Find in terms of t, the position vector of the dinghy t seconds after 2 seconds.
    b) Find the distance of the dinghy from the observation point at 2:05pm

    I can do a) however im struggling with b) ................. i'll quickly run through a) so it will help with answer b)

    a) -500j + (2i + 3j)t = 2ti + (3t-500)j

    help with b) would be much appreciated
    What's the value of t at 2:05 pm? (Watch your units)

    So plug that value into your equation from a) and you have the position. Then pythagoras for the distance.
 
 
 
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