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Find plane of reflection given two images

If the image of I under the operation of reflection in the plane P, find the two possible Cartesian equations of P:

I=x112=y1=z53I=\frac {x-1}{12}=\frac {y}{-1}=\frac {z-5}{3}

I=x28=y3=z59I'=\frac {x-2}{8}=\frac {y}{-3}=\frac {z-5}{9}

I am thinking find a point on each line, AB, have a line through them, then AB=AN cos theta, then dot product?
(edited 11 years ago)
Reply 1
Find one point in the plane (midpoint between a point on one line and the corresponding point on the other line).

Find the direction of the vector between these points. This will be your normal to the plane.
Reply 2
Original post by BabyMaths
Find one point in the plane (midpoint between a point on one line and the corresponding point on the other line).

Find the direction of the vector between these points. This will be your normal to the plane.


But joining any two points on the lines may not necessarily give you the normal vector to the plane, unless one point was a reflection of the other in the plane.
Reply 3
No of course not.

The lines intersect (on the planes of symmetry) and reflected points are equidistant from the point of intersection.

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