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    I've done question 1a and 1b, but I don't seem to be getting the right answer for questions 1c.
    To get 1c I did 242(1.1)^2
    I get 292.82. The answer says 266! What am I doing wrong? Please help


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    200x(1.1)^3 = 266.2

    = 266 ants
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    (Original post by Pilot96)
    I've done question 1a and 1b, but I don't seem to be getting the right answer for questions 1c.
    To get 1c I did 242(1.1)^2
    I get 292.82. The answer says 266! What am I doing wrong? Please help


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    After n years, the number of ants is given by

    \displaystyle 200 \times (1.1)^n
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    (Original post by BananaPie)
    200x(1.1)^3 = 266.2

    = 266 ants
    But don't you use the equation ar^n-1??


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    (Original post by Pilot96)
    But don't you use the equation ar^n-1??


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    the key word is 'after' so 3 years after the initial, n=4. Therefore n-1=3
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    I'm doing the same spec as you and if you are struggling with this or anything else in the specification you should try www.examsolutions.net
    it's really helpful tutorials on everything and has past exam papers. This website has really helped me in this course, give it a look


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    (Original post by Johnathon16)
    I'm doing the same spec as you and if you are struggling with this or anything else in the specification you should try www.examsolutions.net
    it's really helpful tutorials on everything and has past exam papers. This website has really helped me in this course, give it a look


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    Thank you so much!!!


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    (Original post by Pilot96)
    Thank you so much!!!


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    Don't worry about it that has most modules on our course too so check it if your ever stuck on anything


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