Simultaneous equation

I've done all other questions on them, but I'm stuck on this one and it's not even the hardest one (I'm doing the substitution method btw):

x+y^2 = 10
x -2y = 2

Any help as I've tried it twice and got two ridiculous answers both times

I've done all other questions on them, but I'm stuck on this one and it's not even the hardest one (I'm doing the substitution method btw):

x+y^2 = 10
x -2y = 2

Any help as I've tried it twice and got two ridiculous answers both times

So, you have substituted x = 2 + 2y ?

Rearrange the second equation so it becomes x=2y+2.

Then put this value of x into the first equation, so it becomes (2y+2)+y^2=10.

This becomes:

y^2+2y-8=0

Factorise this to get (y+4)(y-2)=0.

You should be able to solve it from their to get two values of y.

Use these to find possible values of x.

You should try substituting x = 2 + 2y into x + y^2 = 10. The answer is in the spoiler but don't click on it until you've tried it for yourself



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Oops no, I kept rearranging to find Y = ... not X, that was my big mistake



I followed all of this, proceeded and I got Y = -4, X = -6 and Y = 2, X = 6. Is this what you ended up with as well haha?



See above post as to the answer I got, not sure whether I'm correct

Your answers are correct