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Var(Sn) probability generating function

I have X1 X2, ..... being i.i.d.r.v
Sn is the sum of them.

I have shown that the probability generating function of Sn is equal to
GN(GX(z))

How can I use this to calculate that the variance of SN?

Many thanks!!
Reply 1
There is a standard result for the variance from a probability generating function, You need to find the first and second derivatives and then apply

Var(x) = g''(1)+g'(1)-[g'(1)]^2

Proof is in your lecture notes i supose, or a quick google yields http://www.cl.cam.ac.uk/teaching/0708/Probabilty/prob06.pdf
(edited 10 years ago)
Reply 2
Original post by lubus
There is a standard result for the variance from a probability generating function, You need to find the first and second derivatives and then apply

Var(x) = g''(1)+g(1)-[g'(1)]^2Typo here I think.

RHS should be g(1)+g(1)(g(1))2g''(1) + g'(1) - (g'(1))^2.
Reply 3
Yep I've got that formula thanks.

Not sure how to differentiate the product of the generating functions though


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Reply 4
Original post by TommyCricket
Yep I've got that formula thanks.

Not sure how to differentiate the product of the generating functions thoughIt's not a product, it's a composition of functions.

Spoiler

Reply 5
Sorry I meant chain rule. Still not sure how to calculate the derivatives of p.g.f


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