If there are 8 alpha decays involved in the sequence of decays from;
238 U to 206 Pb 92 82
how many beta decays are involved?
I don't understand the mark scheme for this answer, so an explanation would be appreciated
Alpha decays emit alpha particles, which have a mass of 4 and a charge of 2. By emitting 8 alpha particle, the mass number will be reduced by 32 and the proton number will be reduced by 16.
Can you do the rest? (remembering that a beta particle has 'no' mass and a charge of -1)