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# In a circuit(electricity) watch

1. In a circuit where there are 2 resistors in parallel do they have the same voltage flowing through them no matter the resistance?
2. No, the voltage is only same for resistors in parallel.
Series circuit have the same current flowing through them.
3. (Original post by thefatone)
In a circuit where there are 2 resistors in parallel do they have the same voltage flowing through them no matter the resistance?
Voltage doesnt really flow as such, but the voltage across them woukd be the same (provided they are the only component in each branch)
4. (Original post by samb1234)
Voltage doesnt really flow as such, but the voltage across them woukd be the same (provided they are the only component in each branch)
thanks, my mistake
so for example in this random pic i got off the interwebs the voltage across both resistors would be the same?

5. (Original post by thefatone)
thanks, my mistake
so for example in this random pic i got off the interwebs the voltage across both resistors would be the same?

Yup, the potential difference across each resistor is the same it's just the current (and hence power dissipated) which is different.
6. (Original post by thefatone)
thanks, my mistake
so for example in this random pic i got off the interwebs the voltage across both resistors would be the same?

Yes it would be. Just a tip for questions involving lightbulbs, a fairly common question is where they have 2 bulbs and one is brighter in series and the other is brighter when in parallel, and they ask you to explain why/which has the higher resistance. Remember that the brightness is essentially a measure of the power dissipated, and you hopefully know that p=v^2/r or P=I^2 R. In series, I is constant so using the second we can easily see that the bulb with the higher resistance is brighter. In parallel, the voltage is the same so we can see that the one with the higher resistance will be less bright from the first equation
7. (Original post by samb1234)
Yes it would be. Just a tip for questions involving lightbulbs, a fairly common question is where they have 2 bulbs and one is brighter in series and the other is brighter when in parallel, and they ask you to explain why/which has the higher resistance. Remember that the brightness is essentially a measure of the power dissipated, and you hopefully know that p=v^2/r or P=I^2 R. In series, I is constant so using the second we can easily see that the bulb with the higher resistance is brighter. In parallel, the voltage is the same so we can see that the one with the higher resistance will be less bright from the first equation
thanks help here too pls

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