Clarification on emf
Is emf of a cell basically how far to the left or right the equilibrium is? Does it show you, with respect to the standard hydrogen electrode, how much better of a reducing/oxidising agent it is?? I’m so confused. Please can someone properly clarify this for me.
"You're unbelievable."
The electrode potential values (which are collected WRT the H2 electrode) tell you how far to the LHS or RHS an equilibrium is (assuming standard conditions) and hence whether that half cell is an oxidising or reducing agent and how good it is at stealing/donating e-.
The electrode potential values (which are collected WRT the H2 electrode) tell you how far to the LHS or RHS an equilibrium is (assuming standard conditions) and hence whether that half cell is an oxidising or reducing agent and how good it is at stealing/donating e-.
Original post by Pigster
"You're unbelievable."
The electrode potential values (which are collected WRT the H2 electrode) tell you how far to the LHS or RHS an equilibrium is (assuming standard conditions) and hence whether that half cell is an oxidising or reducing agent and how good it is at stealing/donating e-.
The electrode potential values (which are collected WRT the H2 electrode) tell you how far to the LHS or RHS an equilibrium is (assuming standard conditions) and hence whether that half cell is an oxidising or reducing agent and how good it is at stealing/donating e-.
Why am I unbelievable
Original post by hello654321
Why am I unbelievable
https://www.youtube.com/watch?v=LdfOqPhV3jY
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