I've drawn the mechanism for this reaction and attached it.
The first step is where the pi-bond in propene induces a dipole in Cl2, and this causes the pi-bond to attack the delta-positive end of Cl2. The covalent bond in Cl2 undergoes heterolytic fission, hence forming a carbocation intermediate along with a chloride ion.
In the second step, the chloride ion acts as a nucleophile as it has a lone pair of electrons, which the carbocation can accept. Hence, this nucleophile attacks the carbocation, and forms a new C-Cl bond - the reaction is then complete.
The product formed is 1,2-dichloropropane.
The first step is where the pi-bond in propene induces a dipole in Cl2, and this causes the pi-bond to attack the delta-positive end of Cl2. The covalent bond in Cl2 undergoes heterolytic fission, hence forming a carbocation intermediate along with a chloride ion.
In the second step, the chloride ion acts as a nucleophile as it has a lone pair of electrons, which the carbocation can accept. Hence, this nucleophile attacks the carbocation, and forms a new C-Cl bond - the reaction is then complete.
The product formed is 1,2-dichloropropane.
(edited 5 years ago)
Original post by Kian Stevens
I've drawn the mechanism for this reaction and attached it.
The first step is where the pi-bond in propene induces a dipole in Cl2, and this causes pi-bond to attack the delta-positive end of Cl2. The covalent bond in Cl2 undergoes heterolytic fission, hence forming a carbocation intermediate along with a chloride ion.
In the second step, the chloride ion acts as a nucleophile as it has a lone pair of electrons, which the carbocation can accept. Hence, this nucleophile attacks the carbocation, and forms a new C-Cl bond - the reaction is then complete.
The product formed is 1,2-dichloropropane.
The first step is where the pi-bond in propene induces a dipole in Cl2, and this causes pi-bond to attack the delta-positive end of Cl2. The covalent bond in Cl2 undergoes heterolytic fission, hence forming a carbocation intermediate along with a chloride ion.
In the second step, the chloride ion acts as a nucleophile as it has a lone pair of electrons, which the carbocation can accept. Hence, this nucleophile attacks the carbocation, and forms a new C-Cl bond - the reaction is then complete.
The product formed is 1,2-dichloropropane.
thank you for this
)Original post by funtz
I think this is about free radical subsitution.
It would be radical substitution if it was propane and chlorine (in the presence of UV).
However, this is propene and chlorine, hence the mechanism will be electrophilic addition.
Quick Reply
Related discussions
- SN1 and SN2 reactions (chemistry)
- A Level Chemistry Organic Help
- chemistry a level
- amines
- Chemistry help
- Do you need to know Acylation mechanism for A level OCR chemistry ?
- Could someone please help with a mechansim question.
- Organic chemistry learning a-level
- outline a mechanism for the reaction of bromomethane with an excess of compound J
- PLEASE Help ME-CHEMISTRY 😭
- Chemistry aqa a-level organic
- AQA A Level Chemistry
- ocr a level chemistry mechanisms and pathways
- OCR AS Chemistry- nucleophilic subs. reaction
- For each of the following reactions, predict the structures of the main products that
- Edexcel Organic chemistry and paper 3
- NO catalysing ozone depletion
- Ask Us Anything!
- Chemistry alevel mechanisms
- Biochemistry Personal Statement Example
Latest
Trending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these productsTrending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these products
