This is the question type i'm stuck on.

A sample of copper was analysed and found to contain two isotopes, 63-copper

and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic

energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions

took 1.829 x 10^–5 s.

How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the

same flight tube?

Give your answer to the appropriate number of significant figures.

Show your working.

The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.

It might seem obvious but i keep getting these wrong so someone please help me.

A sample of copper was analysed and found to contain two isotopes, 63-copper

and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic

energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions

took 1.829 x 10^–5 s.

How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the

same flight tube?

Give your answer to the appropriate number of significant figures.

Show your working.

The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.

It might seem obvious but i keep getting these wrong so someone please help me.

(edited 4 years ago)

Original post by Vhewitt

Ke = 1/2 mv^2

V= distance / time

V= distance / time

Hey thanks for the reply but thats not what i mean.

I get what your saying they are required but im talking about the time aspect of v=distance over time and how it looks if you substitute it into the entirety of the kinetic energy equation.

Original post by username4563432

This is the question type i'm stuck on.

A sample of copper was analysed and found to contain two isotopes, 63-copper

and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic

energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions

took 1.829 x 10^–5 s.

How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the

same flight tube?

Give your answer to the appropriate number of significant figures.

Show your working.

The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.

It might seem obvious but i keep getting these wrong so someone please help me.

A sample of copper was analysed and found to contain two isotopes, 63-copper

and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic

energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions

took 1.829 x 10^–5 s.

How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the

same flight tube?

Give your answer to the appropriate number of significant figures.

Show your working.

The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.

It might seem obvious but i keep getting these wrong so someone please help me.

65Cu+ = 65 Relative Atomic Mass

65/1.079 x 10^-25 = 6.024 x 10^26

Convert to Kg = 6.024 x 10^29

im not sure if you divide but the length is relevant in the question

Times the answer by the length?

Answer = 4.8192 x 10^29

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