mass spectrometry and rearranging the kinetic energy equation
This is the question type i'm stuck on.
A sample of copper was analysed and found to contain two isotopes, 63-copper
and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic
energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions
took 1.829 x 10^–5 s.
How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the
same flight tube?
Give your answer to the appropriate number of significant figures.
Show your working.
The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.
It might seem obvious but i keep getting these wrong so someone please help me.
A sample of copper was analysed and found to contain two isotopes, 63-copper
and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic
energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions
took 1.829 x 10^–5 s.
How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the
same flight tube?
Give your answer to the appropriate number of significant figures.
Show your working.
The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.
It might seem obvious but i keep getting these wrong so someone please help me.
(edited 4 years ago)
Original post by Vhewitt
Ke = 1/2 mv^2
V= distance / time
V= distance / time
Hey thanks for the reply but thats not what i mean.
I get what your saying they are required but im talking about the time aspect of v=distance over time and how it looks if you substitute it into the entirety of the kinetic energy equation.
Original post by username4563432
This is the question type i'm stuck on.
A sample of copper was analysed and found to contain two isotopes, 63-copper
and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic
energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions
took 1.829 x 10^–5 s.
How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the
same flight tube?
Give your answer to the appropriate number of significant figures.
Show your working.
The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.
It might seem obvious but i keep getting these wrong so someone please help me.
A sample of copper was analysed and found to contain two isotopes, 63-copper
and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic
energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions
took 1.829 x 10^–5 s.
How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the
same flight tube?
Give your answer to the appropriate number of significant figures.
Show your working.
The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.
It might seem obvious but i keep getting these wrong so someone please help me.
65Cu+ = 65 Relative Atomic Mass
65/1.079 x 10^-25 = 6.024 x 10^26
Convert to Kg = 6.024 x 10^29
im not sure if you divide but the length is relevant in the question
Times the answer by the length?
Answer = 4.8192 x 10^29
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