# mass spectrometry and rearranging the kinetic energy equation

This is the question type i'm stuck on.
A sample of copper was analysed and found to contain two isotopes, 63-copper
and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic
energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions
took 1.829 x 10^–5 s.
How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the
same flight tube?
The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.
(edited 4 years ago)
Ke = 1/2 mv^2
V= distance / time
Original post by Vhewitt
Ke = 1/2 mv^2
V= distance / time

Hey thanks for the reply but thats not what i mean.
I get what your saying they are required but im talking about the time aspect of v=distance over time and how it looks if you substitute it into the entirety of the kinetic energy equation.
This is the question type i'm stuck on.
A sample of copper was analysed and found to contain two isotopes, 63-copper
and 65-copper. All the ions were accelerated to have 1.000 x 10^-16 J of kinetic
energy and travelled through a flight tube that was 0.8000 m long. 63Cu+ions
took 1.829 x 10^–5 s.
How long would 65Cu+ ions of mass 1.079 x 10^–25 kg take to travel along the
same flight tube?
The issue i'm having is that i can work out all the values required for the equation but i dont understand how i can rearrange the kinetic energy formula to find the Time of flight.

65Cu+ = 65 Relative Atomic Mass
65/1.079 x 10^-25 = 6.024 x 10^26
Convert to Kg = 6.024 x 10^29
im not sure if you divide but the length is relevant in the question
Times the answer by the length?