Derivative of cosec^3(x)
I tried using the chain rule but I keep getting a different answer to the correct one, but I can't figure out where I'm going wrong
I rewrote cosec³x as 1/sin³x
then took u as sinx, and du/dx = cosx
so y = 1/u³ = u^-3, so dy/du = -3u^-4
and multiplying du/dx and dy/du = -3(sinx)^-4 x cosx
but the answer is meant to be -3cosecx³cotx
can anyone help? where am I making a mistake?
I rewrote cosec³x as 1/sin³x
then took u as sinx, and du/dx = cosx
so y = 1/u³ = u^-3, so dy/du = -3u^-4
and multiplying du/dx and dy/du = -3(sinx)^-4 x cosx
but the answer is meant to be -3cosecx³cotx
can anyone help? where am I making a mistake?
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