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circles and tangents..? help?

just wondering if anyone can help me....

1) FIND THE EQUATIONS TO THE TANGENTS TO THE CIRCLE

x^2 + y^2 = 25

FROM THE POINT P(2,11), OUTSIDE THE CIRCLE


and...


2) SHOW THAT THE STRAIGHT LINE

x - 3y - 10 = 0

IS A TANGENT TO THE CIRCLE

x^2 + y^2 = 10

BY: (I) FINDING THE DISTANCE OF THE LINE FROM THE ORIGIN
(II) SHOWING THAT THE LINE MEETS THE CIRCLE AT ONE POINT ONLY

FURTHER, DETERMINE THE EQUATION TO THE NORMAL TO THE CIRCLE THROUGH THE POINT OF CONTACT OF THE TANGENT






got really stuck...thanks for any help :smile:
Reply 1
ooh and particularly the first one...im really stuck :frown:
Reply 2
CCDB
just wondering if anyone can help me....

1) FIND THE EQUATIONS TO THE TANGENTS TO THE CIRCLE

x^2 + y^2 = 25

FROM THE POINT P(2,11), OUTSIDE THE CIRCLE


you should know dydx\frac{dy}{dx} givens you the gradients of the tangents to the curve, so using implicit differentiation (let me know if you need me to explain this concept, i'll assume you know it already to save time):

[spoiler]

2x+2ydydx=02x + 2y\frac{dy}{dx} = 0

2ydydx=2x2y\frac{dy}{dx} = -2x

dydx=2x2y\frac{dy}{dx} = \frac{-2x}{2y}

dydx=xy\frac{dy}{dx} = \frac{-x}{y}

subbing in the values x=2x = 2 and y=11y = 11 you get

dydx=211\frac{dy}{dx} = \frac{-2}{11}

now using the formula yy1=m(xx1)y - y_1 = m(x - x_1) to find an equation of a line we get

y11=211(x2)y - 11 = \frac{-2}{11}(x - 2)


y=2x11+411+11y = \frac{-2x}{11} + \frac{4}{11} + 11

y=2x11+12511\therefore y = \frac{-2x}{11} + \frac{125}{11} or 11y+2x125=0[br][br]11y + 2x - 125 = 0[br][br]
Reply 3
CCDB

2) SHOW THAT THE STRAIGHT LINE

x - 3y - 10 = 0

IS A TANGENT TO THE CIRCLE

x^2 + y^2 = 10

BY: (I) FINDING THE DISTANCE OF THE LINE FROM THE ORIGIN
(II) SHOWING THAT THE LINE MEETS THE CIRCLE AT ONE POINT ONLY

FURTHER, DETERMINE THE EQUATION TO THE NORMAL TO THE CIRCLE THROUGH THE POINT OF CONTACT OF THE TANGENT


part i

Spoiler



part ii

Spoiler

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