# mymaths vectors help

When you differentiate an exponential like
e^f(t)
Using the chain rule its
f'(t) e^f(t)
so the exponent does not change.

Also moving perp to the j axis, must mean the velocity has no j component, so its not t=0.
(edited 1 year ago)

When you differentiate a power of e, the power stays the same, so you get 7e^(2t).

When it moves perpendicular to j, the j component of the velocity is 0.

To find the speed you've got to do Pythagoras on the velocity.
Original post by tiny hobbit
When you differentiate a power of e, the power stays the same, so you get 7e^(2t).

When it moves perpendicular to j, the j component of the velocity is 0.

To find the speed you've got to do Pythagoras on the velocity.

thank you i got it!
Original post by mqb2766
When you differentiate an exponential like
e^f(t)
Using the chain rule its
f'(t) e^f(t)
so the exponent does not change.

Also moving perp to the j axis, must mean the velocity has no j component, so its not t=0.

thank you you i got it !