mymaths vectors help

3

https://cdn.discordapp.com/attachments/990723196997226526/1135940483164672100/vectors.png

Something seems off idk how to do this

Reply 1

mqb2766

21

Original post by AnaNik

https://cdn.discordapp.com/attachments/990723196997226526/1135940483164672100/vectors.png

Something seems off idk how to do this

When you differentiate an exponential like
e^f(t)
Using the chain rule its
f'(t) e^f(t)
so the exponent does not change.

Also moving perp to the j axis, must mean the velocity has no j component, so its not t=0.

(edited 1 year ago)

Reply 2

tiny hobbit

15

Original post by AnaNik

https://cdn.discordapp.com/attachments/990723196997226526/1135940483164672100/vectors.png

Something seems off idk how to do this

When you differentiate a power of e, the power stays the same, so you get 7e^(2t).

When it moves perpendicular to j, the j component of the velocity is 0.

To find the speed you've got to do Pythagoras on the velocity.

Reply 3

username4949078

OP

3

Original post by tiny hobbit

When you differentiate a power of e, the power stays the same, so you get 7e^(2t).

When it moves perpendicular to j, the j component of the velocity is 0.

To find the speed you've got to do Pythagoras on the velocity.

thank you i got it!

Reply 4

username4949078

OP

3

Original post by mqb2766

When you differentiate an exponential like
e^f(t)
Using the chain rule its
f'(t) e^f(t)
so the exponent does not change.

Also moving perp to the j axis, must mean the velocity has no j component, so its not t=0.

thank you you i got it !

mymaths vectors help

Related discussions

Articles for you