Bearings

If anyone doesnt mind doing these questions like explaining them bc i got the first few but didnt understand what i was doing 😭. im just gonna post the last one for now but if nobody minds ill send more!

Original post by r_4bi

If anyone doesnt mind doing these questions like explaining them bc i got the first few but didnt understand what i was doing 😭. im just gonna post the last one for now but if nobody minds ill send more!

Best to post your working. From a quick sketch, C is North and a bit West of A, so the bearing of A from C must be ~160 though thats a guestimate.

Reply 2

timmy124324

3

Original post by r_4bi

If anyone doesnt mind doing these questions like explaining them bc i got the first few but didnt understand what i was doing 😭. im just gonna post the last one for now but if nobody minds ill send more!

For the second question, try draw out your triangle first. You will notice you can make a right angle triangle with point S and C, with the S angle being 5 degrees (we know that from question: c is 680m from S). So we know the other angle in the right angle triangle is 85 degrees (at point C). We then have a straight line where we know two angles of three, one is 85 (from triangle), and the other is 60 from 360-60 (from question). Then we can use sine or cosine rule, since we know all three angles and the length of one side.

Bearings

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