PD Between two charged plates
Stupid question, nonetheless, I will ask it :
Supposing I have two charged plates set up with a gap of a distance of xm between them.
These plates are parallel and the elctric field between them is uniform.
Supposing the PD on one plate is +5V and the other is -5V.
What is the electric field strength in terms of x ?
Supposing I have two charged plates set up with a gap of a distance of xm between them.
These plates are parallel and the elctric field between them is uniform.
Supposing the PD on one plate is +5V and the other is -5V.
What is the electric field strength in terms of x ?
Hello ?
The field strength is always the potential difference divided by the distance between the two plates for a parallel plate capacitor.
Original post by Stonebridge
The field strength is always the potential difference divided by the distance between the two plates for a parallel plate capacitor.
Yes, I know that.
Why is the answer 10/x ??
Could you look at this please :
http://www.thestudentroom.co.uk/showthread.php?p=30858767#post30858767
because the formula is E = v/d
Original post by Firewalker123
because the formula is E = v/d
Yes I know that, but shouldnt it be 5/x ??
Original post by Ari Ben Canaan
Yes, I know that.
Why is the answer 10/x ??
Why is the answer 10/x ??
Because the potential difference is 10V.
Original post by Stonebridge
Because the potential difference is 10V.
Ahhhhh..... I see now.
Could you have a look at the other thread, please ?
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