Vectors - Planes

The last part usually the plane is given in Cartesian form and you can just sub the equation of the line into the equation of the plane and find lambda.

In the mark scheme it says the plane x -z is the plane y=0 but I don't get how it is this?

The last part usually the plane is given in Cartesian form and you can just sub the equation of the line into the equation of the plane and find lambda.

In the mark scheme it says the plane x -z is the plane y=0 but I don't get how it is this?

The x-z plane is exactly the same as the y=0 plane.

Yeah, but I don't understand why

think of a two D Cartesian line analogy

Yeah, but I don't understand why

For all value of the X-z plane, y=0


Posted from TSR Mobile

Yeah, but I don't understand why

Ohh, so does that mean the plane x +z is also the plane y= 0 ?

and the plane y +z is the plane x=0

the x - y plane is z = 0
the x - z plane is y = 0
the y - z plane is x = 0

Think about it this way. The z=0 plane is the x-y plane which makes sense because when you think about the x-y plane in 2D, you don't ever consider the Z coordinates because the Z coordinate for any point in the x-y plane is 0.

For all points in the X-z plane, y=0


Posted from TSR Mobile

Ohh, so does that mean the plane x +z is also the plane y= 0 ?

and the plane y +z is the plane x=0