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AQA Physics AS exam 24th MAY and 9th JUNE 2016 (Thread)

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That paper was hard af.

Was hoping for a lot more mechanics as ive completed M1,2,3 but almost nothing came up.

Hopefully the boundaries are really low

Reply 61

rifat12345

I failed. Were the 3 melted parts nodes or antinodes?

Reply 62

thao.lephuong

Guyss what is your answer for the question asking about the suitable material for making lift cable and bungee cable???

I chose D for lift and C for bungee...not sure if its right 😔

Reply 63

HasanRaza1

Original post by rifat12345

I failed. Were the 3 melted parts nodes or antinodes?

Antinodes bro thats why they melted due to the vibration
So the frequency was 2.5x10^9 Hz

Reply 64

NYB

Original post by rifat12345

I failed. Were the 3 melted parts nodes or antinodes?

Melted parts were antinodes.

Reply 65

NYB

Original post by thao.lephuong

Guyss what is your answer for the question asking about the suitable material for making lift cable and bungee cable???

I chose D for lift and C for bungee...not sure if its right 😔

I said D for bungee rope and B for the lift...

Reply 66

Chickenslayer69

I don't understand the frequency chocolate question... did you have to measure the line? I had no idea you had to do that and was really confused. :/

Reply 67

HasanRaza1

Original post by thao.lephuong

Guyss what is your answer for the question asking about the suitable material for making lift cable and bungee cable???

I chose D for lift and C for bungee...not sure if its right 😔

Wasnt D the one that experienced a lot of plastic deformation?
It wouldnt be suitable for a lift cos it would just stretch

I put C for bungee tho, but apparently some people are saying D is also a valid answer

Reply 68

kiwifruit99

Original post by thao.lephuong

Guyss what is your answer for the question asking about the suitable material for making lift cable and bungee cable???

I chose D for lift and C for bungee...not sure if its right 😔

I chose those but the other way around

Reply 69

HasanRaza1

Original post by NYB

Melted parts were antinodes.

What did you get for the frequency of the chocolate bar radiation? 2.5x10^9?

I think so, 12cm

Original post by Chickenslayer69

I don't understand the frequency chocolate question... did you have to measure the line? I had no idea you had to do that and was really confused. :/

I measured the distance between the two antinodes, and then multiplied by 2 to get the wavelength...
Then used the wave speed equation to calculate frequency.

Reply 72

NYB

Original post by rifat12345

I think so, 12cm

I got 11.8 cm

Reply 73

HasanRaza1

Original post by Chickenslayer69

I don't understand the frequency chocolate question... did you have to measure the line? I had no idea you had to do that and was really confused. :/

I measured the length across all three antinodes, which resulted in a length of 11.8cm. That is 0.118m wavelength
Frequency = Speed of light in a vacuo (3x10^8)/Wavelength (0.118)
So f = 2.5x10^9

Reply 74

NYB

Original post by HasanRaza1

What did you get for the frequency of the chocolate bar radiation? 2.5x10^9?

I got that as well...

Reply 75

HasanRaza1

Original post by NYB

I got that as well...

Great did u get 25% as the percentage change?

Reply 76

NYB

Original post by HasanRaza1

Great did u get 25% as the percentage change?

No. I got 605% but I am not sure.

Reply 77

icecubeinferno

Just came home, all i have to do know is wait for the next physics paper. The test was pretty hard but i answered most of the we questions. One thing though, how do u calculate the stopping potential using energy? U are not given coulombs.. So is there some other formula i havent noticed?