Sulfuric acid starts to decompose at around 300 Celsius.
So the reagents need to be aqueous and since the concentrated acid is not aqueous, dilute acid is used instead?
Sulfuric acid starts to decompose at around 300 Celsius - > what does this suggest as the reaction is heated under reflux regardless of whether the acid is dilute or not...
So the reagents need to be aqueous and since the concentrated acid is not aqueous, dilute acid is used instead?
Sulfuric acid starts to decompose at around 300 Celsius - > what does this suggest as the reaction is heated under reflux regardless of whether the acid is dilute or not...
Not sure, but google said the the more dilute it is, the closer it is to 100 degrees. The more concentrated the acid, the higher the boiling point. But I am very lost now.
Not sure, but google said the the more dilute it is, the closer it is to 100 degrees. The more concentrated the acid, the higher the boiling point. But I am very lost now.
So dilute boils at about 100 degrees and concentrated at 337 degrees.
Sulfuric acid starts decomposition at 300 degrees.
Which of dilute and concentrated do you therefore not want to reflux?
So dilute boils at about 100 degrees and concentrated at 337 degrees.
Sulfuric acid starts decomposition at 300 degrees.
Which of dilute and concentrated do you therefore not want to reflux?
So dilute acid is better because you don't want it to decompose. Okay
Does this mean that for all reactions that are heated under reflux, if acid is used as a catalyst it is must be dilute? But for the decomposition bit, do most acid decompose at 300 degrees ?
So dilute acid is better because you don't want it to decompose. Okay
Yeah. Also if you have to dissolve whatever you're oxidising, this may work better with water present than in conc. acid.
Does this mean that for all reactions that are heated under reflux, if acid is used as a catalyst it is must be dilute? But for the decomposition bit, do most acid decompose at 300 degrees ?
Looking at the reaction as an equilibrium: (H2S04) CH3CH2OH↽−−⇀CH2=CH2+H2O
If the sulphuric acid is conc. , there is little presence of water and so the equilibrium will shift to the right and as a result ethanol will be dehydrated.
Whereas, if it was dilute, there is a greater concentration of water and as a result the equilibrium would shift left to form more ethanol.