M2 Centre of mass / moments question

Hello, could someone help me to see how the force is acting on the prism on part ii of this question? https://gyazo.com/f8f20c8cc135fae215e854f9975699a6

Thanks

The force is applied at a tangent point on the arc DE, where the angle is 60 degrees to the vertical (30 to the horizontal).
Imagine the dashed radius a bit until it is 60 degrees with the horizontal. The point on the circumference is the point where the force is acting and its acts in a tangential direction.

what does tangential direction mean, that it acts along the tangent?

Yes, that looks right. Imagine that the surface is very rough so no slippage and the force is acting along the surface.

done thanks, I got some general questions.

In part i since I was told the object is about to topple, I would assume it topples about A cause of the shape the prism is? also the way I did that question was doing centre of masses about A, and then since centre of mass is at A, my cofm would be =0

Afterwards, in part two, does the weight of the object (cofm) still act on A? cause that's the way I did it by doing moments about B. I'm a bit confused would be glad to get this clear.

For part i) you must consider the horizontal component of the COM above A.
For part ii) you're told its in equilibrium on the point of rotating about B. The COM will still be vertically above A, but its about to rotate about B.
So it looks like you're right in both cases.

So the COM of a shape never changes but the point of toppling can basically?
And what if I was told initially that if topples about B, how would I know the COM lies on A?
Sorry for being a pain , just wanna make sure I understand