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OCR (non mei) C4 Friday 24th June 2016

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image.jpg Thought that was the answer to question 3
Original post by Arnaud Lawrence
image.jpg Thought that was the answer to question 3



That is right just in the answers the 1/x^2 in the numerator. So the x^2 multiplies by each term in the denominator.
Can anyone remember exactly what question 3 asked?
Can anyone remember specifically what question 2 was?
Was it:
integral between bounds of pi/16 to pi/8 for (8 - cos^4x) dx or something?
Original post by deadroad
That is right just in the answers the 1/x^2 in the numerator. So the x^2 multiplies by each term in the denominator.

Will I lose marks for that
Original post by Arnaud Lawrence
Will I lose marks for that


I highly doubt it. I put the same answer as well. it is technically correct just the formatting is exponential on the numerator is all.
Original post by deadroad
Can anyone remember specifically what question 2 was?
Was it:
integral between bounds of pi/16 to pi/8 for (8 - cos^4x) dx or something?


It was more like (9-6cos^2x)
Original post by ottocalladine
It was more like (9-6cos^2x)



Oh no... -.- I know where I went wrong now I wrote it down as (9 - 6cos^4(2x)).

Great.
The one where you worked out k and x, did it ask for which values of x is valid???
crap I wrote the differential of 1/x as lnx. what a rookie error
Original post by xtremespec
The one where you worked out k and x, did it ask for which values of x is valid???



Yes it did. Don't worry if you missed it out though, probably only 1 mark.
Original post by cam5morrison
crap I wrote the differential of 1/x as lnx. what a rookie error


i did this also. 5 Marks gone, was hoping for an A* but now struggling for an A :frown:
Reply 232
For 10)ii) did it say that y=1/256 when x=0 and it wanted you to work out what y is when x=2? I can't figure out what mistake I made, got something ridiculous like 1/3000e^2
If you graphed the cubic for all real values of x, that should be 1/2 right???
Is 10i slightly incorrect? Should 2 and -4 not be switched around?
Original post by ottocalladine
It was more like (9-6cos^2x)


It was 9-6cos^2(4x)
Original post by nyxxllis
i did this also. 5 Marks gone, was hoping for an A* but now struggling for an A :frown:


I think that'll be 3/5. lose the answer mark and one of the method marks, so not the end of the world
Original post by Super199
It was 9-6cos^2(4x)


Oh, in which case the integral can be rewritten as:
integral of 12 - 3cos8x correct?
Original post by Sid1234
I dont think that was any easier than June 2014 - I think 57 or 58 for an A*

I wish, more like 63 for an A*
Original post by Samwakelin
I wish, more like 63 for an A*


it wasn't that easy haha

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