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    Name:  image.jpg
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Size:  498.5 KB Thought that was the answer to question 3
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    (Original post by Arnaud Lawrence)
    Name:  image.jpg
Views: 397
Size:  498.5 KB Thought that was the answer to question 3

    That is right just in the answers the 1/x^2 in the numerator. So the x^2 multiplies by each term in the denominator.
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    Can anyone remember exactly what question 3 asked?
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    Can anyone remember specifically what question 2 was?
    Was it:
    integral between bounds of pi/16 to pi/8 for (8 - cos^4x) dx or something?
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    (Original post by deadroad)
    That is right just in the answers the 1/x^2 in the numerator. So the x^2 multiplies by each term in the denominator.
    Will I lose marks for that
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    (Original post by Arnaud Lawrence)
    Will I lose marks for that
    I highly doubt it. I put the same answer as well. it is technically correct just the formatting is exponential on the numerator is all.
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    (Original post by deadroad)
    Can anyone remember specifically what question 2 was?
    Was it:
    integral between bounds of pi/16 to pi/8 for (8 - cos^4x) dx or something?
    It was more like (9-6cos^2x)
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    (Original post by ottocalladine)
    It was more like (9-6cos^2x)

    Oh no... -.- I know where I went wrong now I wrote it down as (9 - 6cos^4(2x)).

    Great.
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    The one where you worked out k and x, did it ask for which values of x is valid???
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    crap I wrote the differential of 1/x as lnx. what a rookie error
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    (Original post by xtremespec)
    The one where you worked out k and x, did it ask for which values of x is valid???

    Yes it did. Don't worry if you missed it out though, probably only 1 mark.
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    (Original post by cam5morrison)
    crap I wrote the differential of 1/x as lnx. what a rookie error
    i did this also. 5 Marks gone, was hoping for an A* but now struggling for an A
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    For 10)ii) did it say that y=1/256 when x=0 and it wanted you to work out what y is when x=2? I can't figure out what mistake I made, got something ridiculous like 1/3000e^2
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    If you graphed the cubic for all real values of x, that should be 1/2 right???
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    Is 10i slightly incorrect? Should 2 and -4 not be switched around?
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    (Original post by ottocalladine)
    It was more like (9-6cos^2x)
    It was 9-6cos^2(4x)
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    (Original post by nyxxllis)
    i did this also. 5 Marks gone, was hoping for an A* but now struggling for an A
    I think that'll be 3/5. lose the answer mark and one of the method marks, so not the end of the world
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    (Original post by Super199)
    It was 9-6cos^2(4x)
    Oh, in which case the integral can be rewritten as:
    integral of 12 - 3cos8x correct?
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    (Original post by Sid1234)
    I dont think that was any easier than June 2014 - I think 57 or 58 for an A*
    I wish, more like 63 for an A*
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    (Original post by Samwakelin)
    I wish, more like 63 for an A*
    it wasn't that easy haha
 
 
 
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