good luck for tomorrow !!! can anyone please explain the question on JAN 10 qs 6b (state and explain which two cells in circuit you would expect to go flat)? i am a bit confused about the answer
good luck for tomorrow !!! can anyone please explain the question on JAN 10 qs 6b (state and explain which two cells in circuit you would expect to go flat)? i am a bit confused about the answer
just done this questions basically as more current passes through c and d as they are in series so get the full current, whereas a and b split the current
the mass of the string is 3.1g and the total length of the string is 0.91m. show that the tension in the string when it is sounding the harmonic shown is about 70N
I think the 6 mark question will be either on finding an I-V characteristic or something to do with oscilloscopes. Maybe something on the photoelectric effect or line emission spectra. Unlikely to be on particles as this came up last year
the mass of the string is 3.1g and the total length of the string is 0.91m. show that the tension in the string when it is sounding the harmonic shown is about 70N
Hi guys... im stuck on question 6 (b) Jan 13 paper! I don't get how to work out the voltage of C-D. Can anyone help?
Thanks in advance
Voltage at C = 12-((20/40)*12) = 6
Voltage at D = 12-((10/15)*12) = 4
6-4 = 2V.
The voltage lost over the resistors is proportional to their resistance. In the B-F strand, the 10k resistor uses double the V as the 5k resistor; hence, (10/15)*12V.
The voltage lost over the resistors is proportional to their resistance. In the B-F strand, the 10k resistor uses double the V as the 5k resistor; hence, (10/15)*12V.