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proving trig identities

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proving trig identities

azamally

hey... need help with this one:

prove sec^2x-cosec^2x= tan^2x-cos^2x

Thanks

Reply 1

MikeL230

Try rewriting

sec^2(x)-cosec^2(x)=\frac{1}{cos^2(x)} - \frac{1}{sin^2(x)}

Reply 2

azamally

MikeL230

Try rewriting

sec^2(x)-cosec^2(x)=\frac{1}{cos^2(x)} - \frac{1}{sin^2(x)}

by combining the fractions i got up to

\frac{tan^2(x)}{sin^2(x)} - \frac{cot^2(x)}{cos^2(x)}

dont know where to go from here

Reply 3

Phugoid

azamally

by combining the fractions i got up to

\frac{tan^2(x)}{sin^2(x)} - \frac{cot^2(x)}{cos^2(x)}

dont know where to go from here

\tan^2(x) = \frac{\sin^2(x)}{\cos^2(x)}

\cot^2(x) = \frac{\cos^2(x)}{\sin^2(x)}

Reply 4

eplison-naught

eh dude your question seems wrong.

Reply 5

eplison-naught

Sorry sorry I dunno how that happened!

Reply 6

eplison-naught

anw your qs should be rather- sec^2 x - cosec^2 x = tan^2 x - 1 is it

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