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    OK basically you have to calculate the magnification of the cell.

    There is an image of the cell, which has a diameter of 8.8cm and there is a scale bar of 4 micrometers (1.9cm).

    Now I'm not lazy or cheating, as I've done the question but not sure if I did it correctly.

    Since I wasn't actually given a value for actual size, I assumed the actual size was 4 micrometers.

    4 micrometers=4*10^-6 metres
    4*10^-6 metres= 4.0*10^-4 centimetres.

    Size of image=8.8cm.

    Magnification= Size of image/actual size
    =8.8cm/4.0*10^-4cm= 22000x
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    (Original post by hamzramz)
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    OK basically you have to calculate the magnification of the cell.

    There is an image of the cell, which has a diameter of 8.8cm and there is a scale bar of 4 micrometers (1.9cm).

    Now I'm not lazy or cheating, as I've done the question but not sure if I did it correctly.

    Since I wasn't actually given a value for actual size, I assumed the actual size was 4 micrometers.

    4 micrometers=4*10^-6 metres
    4*10^-6 metres= 4.0*10^-4 centimetres.

    Size of image=8.8cm.

    Magnification= Size of image/actual size
    =8.8cm/4.0*10^-4cm= 22000x
    If 4 micrometers is equal to 1.9cm, and the cell is 8.8cm, then:
    [8.8/1.9] x 4 x 10-6m = 1.85 x 10^-4m, I believe = 185.26cm
    Therefore, your cell size is 185.26cm, and divide it by 4 x 10^-4cm, to get the magnification.



    That was a rather rushed attempt though! sorry.
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    (Original post by hamzramz)
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    OK basically you have to calculate the magnification of the cell.

    There is an image of the cell, which has a diameter of 8.8cm and there is a scale bar of 4 micrometers (1.9cm).

    Now I'm not lazy or cheating, as I've done the question but not sure if I did it correctly.

    Since I wasn't actually given a value for actual size, I assumed the actual size was 4 micrometers.

    4 micrometers=4*10^-6 metres
    4*10^-6 metres= 4.0*10^-4 centimetres.

    Size of image=8.8cm.

    Magnification= Size of image/actual size
    =8.8cm/4.0*10^-4cm= 22000x
    Actual size = 8.8/1.9 x 4 x 10^-5

    this gives you the actual size in micrometers

    Image size = 8.8 x 10^-5 ( or however you get micrometers, I forget.

    Then use IAM so (8.8x10^-5)/(8.8/1.9x4x10^-5)

    I think! I can't honestly remember lol.
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    rep to narik n joec thanks for the answer,
 
 
 
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