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AQA A Level Biology Paper 1 2018

(2.2) The loss in mass shown in Figure 3 is due to osmosis. The rate of osmosis between 0 and 40 minutes is faster in B (the eight small cubes) than in A (single large cube)

Is the rate of osmosis per mm2 per minute different between A and B during this time? Use appropriate calculations to support your answer. (3)

How would you work out the calculations for this question please?
https://www.physicsandmathstutor.com/pdf-pages/?pdf=https%3A%2F%2Fpmt.physicsandmathstutor.com%2Fdownload%2FBiology%2FA-level%2FPast-Papers%2FAQA%2FPaper-1%2FQP%2FJune%25202018%2520QP.pdf
Question 2.2
(edited 1 year ago)
Personally, I would calculate the rate of osmosis by doing rate = change in mass/time for both A and B. So it would be 62-57/40 = 0.125gmin-1 for the large cube and for the small cubes it would be 62-53/40 = 0.225gmin-1. Then I would say as the rate of osmosis is different, for B it is 0.225gmin-1 and for A it is 0.125gmin-1 this means aning that the rate of osmosis is quicker in B than in A.
Original post by pirateguy27
Personally, I would calculate the rate of osmosis by doing rate = change in mass/time for both A and B. So it would be 62-57/40 = 0.125gmin-1 for the large cube and for the small cubes it would be 62-53/40 = 0.225gmin-1. Then I would say as the rate of osmosis is different, for B it is 0.225gmin-1 and for A it is 0.125gmin-1 this means aning that the rate of osmosis is quicker in B than in A.

ah I c thxx
(edited 1 year ago)
Reply 3
Original post by pirateguy27
Personally, I would calculate the rate of osmosis by doing rate = change in mass/time for both A and B. So it would be 62-57/40 = 0.125gmin-1 for the large cube and for the small cubes it would be 62-53/40 = 0.225gmin-1. Then I would say as the rate of osmosis is different, for B it is 0.225gmin-1 and for A it is 0.125gmin-1 this means aning that the rate of osmosis is quicker in B than in A.

is this enough to get all the marks

just asking as mark scheme talks about the surface areas
Original post by pirateguy27
Personally, I would calculate the rate of osmosis by doing rate = change in mass/time for both A and B. So it would be 62-57/40 = 0.125gmin-1 for the large cube and for the small cubes it would be 62-53/40 = 0.225gmin-1. Then I would say as the rate of osmosis is different, for B it is 0.225gmin-1 and for A it is 0.125gmin-1 this means aning that the rate of osmosis is quicker in B than in A.

You can use that rate alongside the surface areas for the answer. For cube A, each side of the cube is 35mm so 35 x 35= 1225 which is the area of 1 side of the cube, so x by 6 = 7350 which is the total surface area( which is what they want since they asked for mm2).For B, the also used the same lengths cube so the total surface area is the same, but because they cut it again you x 7350 by 2 , which gives you 14700mm2 for B. They said that the RATE is PER mm2 min-1, so you do the Rate which was found divided by the area. So for A its 0.125gmin-1 divided by 7350 = 1.7 x 10-5 and for B its 0.225gmin-1 divided by 14700= 1.5 x 10-5
Original post by KBIOCHEMENG
You can use that rate alongside the surface areas for the answer. For cube A, each side of the cube is 35mm so 35 x 35= 1225 which is the area of 1 side of the cube, so x by 6 = 7350 which is the total surface area( which is what they want since they asked for mm2).For B, the also used the same lengths cube so the total surface area is the same, but because they cut it again you x 7350 by 2 , which gives you 14700mm2 for B. They said that the RATE is PER mm2 min-1, so you do the Rate which was found divided by the area. So for A its 0.125gmin-1 divided by 7350 = 1.7 x 10-5 and for B its 0.225gmin-1 divided by 14700= 1.5 x 10-5

Why is surface area of B times by 2. they say he cuts it 8 times so should it not be times By 8??
Reply 6
Original post by rosiematthews
Why is surface area of B times by 2. they say he cuts it 8 times so should it not be times By 8??

I do it a different way. So big cube is 35 mm and so the surface area is of course 7350 mm^2. Now to get to 8 small cubes from one big cube you need t cut it in a way that all cubes are equal in length, that would make each small cube have a side length of 35/2=17.5 mm (it is helpful if you can draw and visualise it). So now we just do 6(17.5)^2 = 1837.5 and since there are 8 cubes, times it by eight which gives you 14700 mm^2. Hope it makes sense.

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