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sallon
thanks, what if just one is an integer? also, how can you prove it?
Say a is some fixed integer. You can rearrange the equation to get b in terms of a; then for any possible value of a (i.e. integers which don't make you end up dividing by zero) there will be a value of b which satisfies the equation -- it must satisfy it, since all you did was rearrange. So if there is an infinite number of possible values for a, then there is an infinite number of values of b, so there are an infinite number of solutions to the equation.
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