Differentiate

I new to this, and need to help :/

How do i differentiate dy/dx = 1 over X ?

Thank you to anyone who can help.

Regards,

Original post by jamiepango

You can rewrite 1 over x as x^(-1).

You should then be able to differentiate it :smile:

I got x^(-2), Is this correct? :smile:

and cheers for the help

Original post by Mr.Blackwood

I got x^(-2), Is this correct? :smile:

and cheers for the help

dy/dx=ax^(a-1)

(edited 13 years ago)

Original post by Mr.Blackwood

I new to this, and need to help :/

How do i differentiate dy/dx = 1 over X ?

Thank you to anyone who can help.

Regards,

[br][br]\dfrac{1}{x}

is the same as

x^{-1}[br]

and -

\dfrac{dy}{dx} = ax^{a-1}

Therefore

[br]\dfrac{dy}{dx} = -x^{-2}[br][br]

When you differentiate you need to convert everything into powers of x first. :smile:

(edited 13 years ago)

Original post by Mr.Blackwood

I got x^(-2), Is this correct? :smile:

and cheers for the help

Almost. You need to muliply the coefficient of x (1) by the original power (-1) first, and then minus one from the power.

f(x) = \frac{1}{x}

f(x) = x^{-1}[br][br][br]\dfrac{dy}{dx}= -x^{-2}[br][br]

Any specific reason I've been negged? Nice to know that's what you get for trying to help.

(edited 13 years ago)

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