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    I new to this, and need to help :/

    How do i differentiate dy/dx = 1 over X ?

    Thank you to anyone who can help.



    Regards,
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    (Original post by jamiepango)
    You can rewrite 1 over x as x^(-1).

    You should then be able to differentiate it

    I got x^(-2), Is this correct? and cheers for the help
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    (Original post by Mr.Blackwood)
    I got x^(-2), Is this correct? and cheers for the help
    dy/dx=ax^(a-1)
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    (Original post by Mr.Blackwood)
    I new to this, and need to help :/

    How do i differentiate dy/dx = 1 over X ?

    Thank you to anyone who can help.



    Regards,
    



\dfrac{1}{x} is the same as  x^{-1}

    and - \dfrac{dy}{dx} = ax^{a-1}

    Therefore

    

\dfrac{dy}{dx} = -x^{-2}

    When you differentiate you need to convert everything into powers of x first.
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    (Original post by Mr.Blackwood)
    I got x^(-2), Is this correct? and cheers for the help
    Almost. You need to muliply the coefficient of x (1) by the original power (-1) first, and then minus one from the power.

    f(x) = \frac{1}{x}

    f(x) = x^{-1}





\dfrac{dy}{dx}= -x^{-2}

    Any specific reason I've been negged? Nice to know that's what you get for trying to help.
 
 
 
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Updated: March 25, 2011
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