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Differential Equations Help

2x+1dydx=expy\sqrt{2x+1} \frac{dy}{dx} = \exp ^{y}



Where x =4 and y=0

So I have this question and you need to find the general solution. So I thought you integrated and then sub in the values of x and y to work out c.

So far though, I have this ....

(2x+1)1/2=y+c(2x+1)^{1/2} = y+c

Could some very helpful person please tell me if I am headed in the right direction?
The integral of e^-y with respect to y is not y.

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