Mole calculation help :)
Ah I absolutely am blindfolded when it comes to mole calc. So here's the question , 2Cu(No3)2->2CuO + 4No2 + O2
1200 cm^3 of no2 gas is produced at rtp.
Hence , deduce the number of molecules of oxygen produced .
Could this be the answer ? Thanks in advance !
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1200 cm^3 of no2 gas is produced at rtp.
Hence , deduce the number of molecules of oxygen produced .
Posted from TSR Mobile
Why have you divided by 2 in the last step? You don't need to 
Whoops my bad haha I think my reverie was along the lines such that I just found the number of atoms , and that molecules were half that number , no?
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Posted from TSR Mobile
You found the number of molecules using the 4:1 ratio, you'd have to double it to find the number of oxygen atoms 
Original post by EierVonSatan
You found the number of molecules using the 4:1 ratio, you'd have to double it to find the number of oxygen atoms
Ahh right ! Haha thanks for your help
) this paper has no mark scheme whatsoever sigh . Thanks mate have a nice day Posted from TSR Mobile
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