Differentiation !

Does limit as x tends to 1 of( √(1-x) ) exist

Posted from TSR Mobile

it tends to being 0.

lim as x tends to 1 right (1+)doesnt exist ..so how does limit as x tends to 1 exist !

Posted from TSR Mobile

I cant understand what are you saying ..
What do you mean by english (Obviously I am writing in english )
So you agree that lim when x tends to 1 doesnt exist ? ..

Posted from TSR Mobile

I can't understand what you are saying, hence why I said English. The limit when x tends to 1, of your original expression is 0. That is it. It does exist, and the answer is

In order that we could say the limit exist when x tends to any number , the left limit and the right limit have to be equal , Right?!!
In this proplem .. the right limit doesn't exist ...So how could we say that the limit when x tends to 1 exist ?


Posted from TSR Mobile

If you are considering this as a function from real numbers to real numbers then your function is only defined for x<1, so only the left-hand limit exists.