Year 12s: what will be the first way you research your future options? >>

Calculating [OH] in a solution of pH 6

What it says on the tin really, can anyone give me a pointer on how to do this calculation? I feel like it's probably really simple but I can't remember >_< Thanks!

Reply 1

Exon

Use inverse logs to find [H+] then use the ionic product of water

[H+_(aq)][OH-] =

10^{-14}

EDIT: typed it wrong

(edited 10 years ago)

Reply 2

swanderfeild

Kw=[OH-][H+]=1*10^-14 (assuming standard conditions). 10^-pH=[H+]
Just find [H+] using the formula involving pH and substitute that into Kw equation; rearranging it.