Can someone help me with Q10(d), I don't understand why we divide moles NaOH by 3, I though you would divide moles of the carboxylic acid by 3??? I always get confused with handling moles like these http://filestore.aqa.org.uk/subjects/AQA-CHM6X-QP-JUN12.PDF
Can someone help me with Q10(d), I don't understand why we divide moles NaOH by 3, I though you would divide moles of the carboxylic acid by 3??? I always get confused with handling moles like these http://filestore.aqa.org.uk/subjects/AQA-CHM6X-QP-JUN12.PDF
I'm not sure of the context of your statement highlighted in red.
But the calculations along the way should involve moles of carboxylic acid = (moles of NaOH/3)