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Praticing n=m/M and 6.02x10^23

Ok, so I decided to have a little fun with the equation for moles and Avogadro's constant, but insure if I have the right answer.

I decided to see how many atom of carbon are in a plastic spoon (assuming the plastic spoon is pure carbon)
The plastic spoon weights 2g
The atomic mass of carbon is 12

My calculations -
2/12= 0.1666666667
0.1666666667 x 6.02x10^23 = 1.00333333x10^23

Therefore, there are 1.00333333x10^23 carbon atoms in a plastic spoon that weights 2g.

Is this correct?
Original post by KingAuthor
Ok, so I decided to have a little fun with the equation for moles and Avogadro's constant, but insure if I have the right answer.

I decided to see how many atom of carbon are in a plastic spoon (assuming the plastic spoon is pure carbon)
The plastic spoon weights 2g
The atomic mass of carbon is 12

My calculations -
2/12= 0.1666666667
0.1666666667 x 6.02x10^23 = 1.00333333x10^23

Therefore, there are 1.00333333x10^23 carbon atoms in a plastic spoon that weights 2g.

Is this correct?


yes

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