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    Name:  1470602306465-1676330518.jpg
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Size:  526.3 KBHi, can I get some help with d? I struggle to work out the volume of air needed and I don't get the last step I need to do.Attachment 568638568640 this is as far as I got for hi) but the answer doesn't make sense because it mentioned 21% of something. Thanks
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    (Original post by coconut64)
    Name:  1470602306465-1676330518.jpg
Views: 62
Size:  526.3 KBHi, can I get some help with d? I struggle to work out the volume of air needed and I don't get the last step I need to do.Attachment 568638568640 this is as far as I got for hi) but the answer doesn't make sense because it mentioned 21% of something. Thanks
    I cant see thr second pic, could you post it again

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    (Original post by coconut64)
    Name:  1470602306465-1676330518.jpg
Views: 62
Size:  526.3 KBHi, can I get some help with d? I struggle to work out the volume of air needed and I don't get the last step I need to do.Attachment 568638568640 this is as far as I got for hi) but the answer doesn't make sense because it mentioned 21% of something. Thanks
    What you've done looks fine assuming that the reaction takes place at standard temperature and pressure (273K, 100kPa). As you've written, at standard temperature and pressure, one mole of any gas occupies a volume of approximately 24dm3. It would probably be best to convert your answer to dm3 though, which would be 7.92dm3.
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    (Original post by Jpw1097)
    What you've done looks fine assuming that the reaction takes place at standard temperature and pressure (273K, 100kPa). As you've written, at standard temperature and pressure, one mole of any gas occupies a volume of approximately 24dm3. It would probably be best to convert your answer to dm3 though, which would be 7.92dm3.
    Hi, the answer is 21% of 7.92. I get it now thanks anyway
 
 
 
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