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    P inversely proportional to V

    if P changes by 2/3 does this mean V changes by 3/2?
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    (Original post by khanpatel321)
    P inversely proportional to V

    if P changes by 2/3 does this mean V changes by 3/2?
    Nope

    What's the question? As far as I know there's a constant which is either given or you have to calculate it using the information provided in the question.

    Equation for this relation would be: P=k/v (k being the constant)
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    (Original post by TheCe)
    Nope

    What's the question? As far as I know there's a constant which is either given or you have to calculate it using the information provided in the question.

    Equation for this relation would be: P=k/v (k being the constant)
    Pressure is inversely proportional to volume.

    Initial pressure = P0 Initial volume = V0

    after a process the new pressure = 2/3(P0) What is the new volume?
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    If you're talking about multiplying when you say change then yes. If P is inversely proportional to V then  P=\frac{k}{V} (k is constant). If we replace V with 2V we get  P=\frac{k}{2V} and so P has halved.

    (Original post by khanpatel321)
    Pressure is inversely proportional to volume.

    Initial pressure = P0 Initial volume = V0

    after a process the new pressure = 2/3(P0) What is the new volume?
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    (Original post by B_9710)
    If you're talking about multiplying when you say change then yes. If P is inversely proportional to V then  P=\frac{k}{V} (k is constant). If we replace V with 2V we get  P=\frac{k}{2V} and so P has halved.
    P is inversely proportional to V

    Initial pressure = P0 Initial volume = V0

    After process 1

    Pressure P1 = (2/3) * P0 So is V1 = (3/2)V0

    Thank you
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    (Original post by khanpatel321)
    P is inversely proportional to V

    Initial pressure = P0 Initial volume = V0

    After process 1

    Pressure P1 = (2/3) * P0 So is V1 = (3/2)V0

    Thank you
    Yes.
 
 
 
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