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Proving a limit with exponentials

How do I prove that $lim{x\rightarrow \infty$$\frac{25x^2}{exp(10x)}=0$?

First consider $$lim{x\rightarrow \infty$$\frac{5x}{exp(5x)}$

Capture.PNG

Thanks.
(edited 7 years ago)
Well, can you find the 2nd limit?
Original post by FrancisHannah
How do I prove that $lim{x\rightarrow \infty$$\frac{25x^2}{exp(10x)}=0$?

First consider $$lim{x\rightarrow \infty$$\frac{5x}{exp(5x)}$

Capture.PNG

Thanks.


For the first note that exp(10x)=e10x=e5x×2\exp(10x)=e^{10x} = e^{5x \times 2}

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