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Has anyone done reduced mass of system before???
Hi,
As per the title?
Basically, I have the following question, but I'm kinda struggling:
1) give an eqn for the reduced mass of the Li2+ system, in terms of mass of nucleus and mass of electron.
As Li in it's atomic state has 3 electrons, and 4 protons+3 nuetrons, and Li2+ has 1 e- and same nuclear contents I've put it as:
u = (Me.7Mn)/(Me+7Mn)
Where Me = mass of electron, and Mn = mass of nucleus
2) Hence calculate the reduced mass and a more accurate energy for n=4 for Li2+
I've calculated the reduced mass to 9.108x10^-31 which I've plugged into R = (e^4.u)/8.Eo^2.h^3.c) but I keep getting the top to be 0... for some reason.
I know the equation, and I know the theoretical method for calculating it, but I'm missing something, and I don't know why
If anyone can help it'd be greatly appreciated.
Thanks
Ourkid
As per the title?
Basically, I have the following question, but I'm kinda struggling:
1) give an eqn for the reduced mass of the Li2+ system, in terms of mass of nucleus and mass of electron.
As Li in it's atomic state has 3 electrons, and 4 protons+3 nuetrons, and Li2+ has 1 e- and same nuclear contents I've put it as:
u = (Me.7Mn)/(Me+7Mn)
Where Me = mass of electron, and Mn = mass of nucleus
2) Hence calculate the reduced mass and a more accurate energy for n=4 for Li2+
I've calculated the reduced mass to 9.108x10^-31 which I've plugged into R = (e^4.u)/8.Eo^2.h^3.c) but I keep getting the top to be 0... for some reason.
I know the equation, and I know the theoretical method for calculating it, but I'm missing something, and I don't know why
If anyone can help it'd be greatly appreciated.
Thanks
Ourkid
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