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4(sin(^4)x + cos(^4)x)=cos4x + 3

How would I solve this inequality.

I have tried solving it from LHS, by making all the terms = sinx

I have got 4(1-2cos(^2)x +2cos(^4)x)

I have now tried using algebraic division to find out what x equals. But I think this is wrong

Any suggestions and help will be appreciated
Reply 1
Original post by BULL14
How would I solve this inequality.

I have tried solving it from LHS, by making all the terms = sinx

I have got 4(1-2cos(^2)x +2cos(^4)x)

I have now tried using algebraic division to find out what x equals. But I think this is wrong

Any suggestions and help will be appreciated


This isn't an inequality. It's an identity. You're not meant to be finding x. You're meant to show it holds for all x.

Can you see how to? Just use double angle identities a few times.
Reply 2
Original post by Zacken
This isn't an inequality. It's an identity. You're not meant to be finding x. You're meant to show it holds for all x.

Can you see how to? Just use double angle identities a few times.


So should I start from rhs
i would start on the left...

sin4x can be written as sin2xsin2x

and sin2x can be written as 0.5 { 1 - Cos2x }
Reply 4
Original post by the bear
i would start on the left...

sin4x can be written as sin2xsin2x

and sin2x can be written as 0.5 { 1 - Cos2x }


Where does the 0.5 come from?
Original post by BULL14
Where does the 0.5 come from?


so Cos(2x) can be expressed as 1 - 2sin2x.... rearrange it.

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