Turn on thread page Beta
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by NineOfDiamonds)
    Ok so I’ve done,

    (x+6)^3 (1(x+6))(3x+4).

    Is this right? If so what do I do next?
    I don't know if you just mistyped but it should be

    (x+6)^3[(x+6)+(3x+4)]

    Notice how this is the same as

    y^3(y+z)

    But with y=(x+6) and z=(3x+4) so the same factorising has happened here.

    You just need to add the two terms in the bracket and you're done.
    • Thread Starter
    Offline

    7
    ReputationRep:
    (Original post by Notnek)
    I don't know if you just mistyped but it should be

    (x+6)^3[(x+6)+(3x+4)]

    Notice how this is the same as

    y^3(y+z)

    But with y=(x+6) and z=(3x+4) so the same factorising has happened here.

    You just need to add the two terms in the bracket and you're done.
    No I did put the addition signs in but it just didn’t show for some reason. I thought I couldn’t add (x+6) to (3x+4) because they should be multiplied?
    Posted on the TSR App. Download from Apple or Google Play
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by NineOfDiamonds)
    No I did put the addition signs in but it just didn’t show for some reason. I thought I couldn’t add (x+6) to (3x+4) because they should be multiplied?
    No if you look at

    y^3(y+z)

    there is a + sign between y and z inside the brackets so there must be a + sign between (x+6) and (3x+4).

    The final step is to add together (x+6) and (3x+4).
    • Thread Starter
    Offline

    7
    ReputationRep:
    (Original post by Notnek)
    No if you look at

    y^3(y+z)

    there is a + sign between y and z inside the brackets so there must be a + sign between (x+6) and (3x+4).

    The final step is to add together (x+6) and (3x+4).
    What do I do about the 1 that is already inside the brackets? Do I add that as well?
    Posted on the TSR App. Download from Apple or Google Play
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by NineOfDiamonds)
    What do I do about the 1 that is already inside the brackets? Do I add that as well?
    1 times by anything is itself so you can ignore the 1.
    • Thread Starter
    Offline

    7
    ReputationRep:
    (Original post by Notnek)
    1 times by anything is itself so you can ignore the 1.
    So is my final answer:

    (x+6)^3(4x+10)?
    Posted on the TSR App. Download from Apple or Google Play
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by NineOfDiamonds)
    So is my final answer:

    (x+6)^3(4x+10)?
    Yes that's right.

    Don't worry if you found that hard - most students do the first time they tackle a question like this. After practicing a few like this I'm sure you'll be fine.
    • Thread Starter
    Offline

    7
    ReputationRep:
    (Original post by Notnek)
    Yes that's right.

    Don't worry if you found that hard - most students do the first time they tackle a question like this. After practicing a few like this I'm sure you'll be fine.
    Thank you very much
    Posted on the TSR App. Download from Apple or Google Play
    Online

    21
    ReputationRep:
    (Original post by NineOfDiamonds)
    Which 2 terms?
    You should have got it factorised as

    (x+6)^3 ((x+6)+(3x+4))

    So you add the two terms in the right hand pair of parentheses.
    • Thread Starter
    Offline

    7
    ReputationRep:
    (Original post by MR1999)
    You should have got it factorised as

    (x+6)^3 ((x+6)+(3x+4))

    So you add the two terms in the right hand pair of parentheses.
    Thanks
    Posted on the TSR App. Download from Apple or Google Play
 
 
 

3,390

students online now

800,000+

Exam discussions

Find your exam discussion here

Poll
Should predicted grades be removed from the uni application process
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.