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    Q.)3 identical circles inside of a rectangle. Each circle touches the other two circles and the sides of a rectangle. The radius of each is 28mm.what is the area of the rectangle (to 3 s.g.f)

    PLEASE HELP!!!!
    question from mathswatch "GCSE revision pythagoras 2d"
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    (Original post by drangonfruit)
    Q.)3 identical circles inside of a rectangle. Each circle touches the other two circles and the sides of a rectangle. The radius of each is 28mm.what is the area of the rectangle (to 3 s.g.f)

    PLEASE HELP!!!!
    question from mathswatch "GCSE revision pythagoras 2d"
    What does your diagram look like?

    How will you be able to use Pythagoras?
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    If you provided a diagram, it would be easier for us to help out
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    An equilateral triangle is made if you join the 3 circles' radius. Split the triangle in half to get 2 right-angled triangles and then use trig as you know that angles in an equilateral triangle are 60 degrees. That will give you the height between the circle. Add the 2 radii to the length you worked out to give you the height of the rectangle. And then just find the area
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