Solve for x where log2(11.-6x) = 2log2(x-1)+3

OJ Emporium

Had a hard time trying to figure this out

Reply 1

have

Original post by OJ Emporium

Had a hard time trying to figure this out

write the +3 on the end as log_2(8)
and then do some log rules till you get
log_2(....) = log_2(.....)
and then just equate the expressions inside the brackets.

Reply 2

bby10.

log2(1-6x)=2log2(x-1) 3

Reply 3

davros

Original post by bby10.

log2(1-6x)=2log2(x-1) 3

Were you trying to help out the OP? This thread is 2 years old!

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