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C2 Geometric sequence question

The fish in a particular area of the north sea are being reduced by 6% each year due to overfishing. How long would it be before the fish stocks are halved?

I would be grateful if someone can show me the working out to get to the answer.
Reply 1
It's quite simple, actually. You have to find 0.94^n = 0.5 and then turn n into years and months. :smile:
Reply 2
The amount of fish left after nn years is arnar^n where a is the starting amount of fish and r is the common ratio.
Reply 3
Original post by satisverborum2003
The fish in a particular area of the north sea are being reduced by 6% each year due to overfishing. How long would it be before the fish stocks are halved?

I would be grateful if someone can show me the working out to get to the answer.


First take 6% from 100% which would be the common ratio r. The answer would be r=0.94.
You would have to take logs to work out the answer to this question.
log(0.94)^x>log(0.5
x>log(0.5 / log(0.95
x= 11.2 years (3 sig.fig )

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