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differentiation help

For f(x) = 12 - 4x + 2x^2, find the equations of the tangent and the normal at the point where x=-1 on the curve with the equation y=f(x)

so i put x in to get y so (-1,18)
i differentiated f(x) and i got 4x-4 so the gradient is 4

what do i do next i'm so confused
Reply 1
Original post by earthworm206
For f(x) = 12 - 4x + 2x^2, find the equations of the tangent and the normal at the point where x=-1 on the curve with the equation y=f(x)

so i put x in to get y so (-1,18)
i differentiated f(x) and i got 4x-4 so the gradient is 4

what do i do next i'm so confused

4x-4 is the derivative or "gradient function". You input the x-coordinate and it outputs the gradient. The gradient is not 4 here, what is it?
Original post by Notnek
4x-4 is the derivative or "gradient function". You input the x-coordinate and it outputs the gradient. The gradient is not 4 here, what is it?

the gradient is -8?
Original post by earthworm206
the gradient is -8?

Correct
4 * (-1) - 4 = -4 - 4 = -8
Reply 4
Original post by earthworm206
the gradient is -8?

Sorry I didn't get a notification when you quoted me for some reason. Do you know what to do next?
Guys, thanks for the responses. I went over the question with my teacher and turns out the mark scheme is incorrect. I kept doing the question over and over again, trying to see where I went wrong but I guess I wasn't lol.

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