(ii) Calculate the initial rate of reaction Help
(ii) Calculate the initial rate of reaction if the experiment is repeated under the sameconditions but with the concentrations of NO and of H2 both doubled from their original values.
here are the values from the previous question
The initial rate of reaction was 6.2 × 10–6 mol dm–3 s–1 when the initial concentration of NO was 2.9 × 10–2 mol dm–3 and the initial concentration of H2 was 2.3× 10–2 mol dm–3.
and the rate constant is 0.32
here are the values from the previous question
The initial rate of reaction was 6.2 × 10–6 mol dm–3 s–1 when the initial concentration of NO was 2.9 × 10–2 mol dm–3 and the initial concentration of H2 was 2.3× 10–2 mol dm–3.
and the rate constant is 0.32
just did this question! just do rate=k([NO]x2)(x2)
rate=(0.32)((2.9x10-2)x2)((2.3x10-2)x2).
******you haven’t provided the rate equation though so depending on thay you could put on corresponding powers if NO or H2 are second order
rate=(0.32)((2.9x10-2)x2)((2.3x10-2)x2).
******you haven’t provided the rate equation though so depending on thay you could put on corresponding powers if NO or H2 are second order
Original post by anikaxox555
just did this question! just do rate=k([NO]x2)(x2)
rate=(0.32)((2.9x10-2)x2)((2.3x10-2)x2).
******you haven’t provided the rate equation though so depending on thay you could put on corresponding powers if NO or H2 are second order
rate=(0.32)((2.9x10-2)x2)((2.3x10-2)x2).
******you haven’t provided the rate equation though so depending on thay you could put on corresponding powers if NO or H2 are second order
******i acidently put in initial rate instead of NO into the equation oops ok thanks
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