Need help on A-level Physics question!Watch
The length of PQ is 0.40 m. When the wire is vibrating, transverse waves are propagated
along the wire at a speed of 64 m s–1. Explain why the wire is set into large amplitude
vibration when the frequency of the a.c. supply is 80 Hz.
wavelength (λ) of waves = = 0.80 (m) (1)
length of wire is λ/2 causing fundamental vibration (1)
[or λ of waves required for fundamental (= 2 × 0.40) = 0.80 m (1)
natural frequency of wire = 80 (Hz) (1)]
wire resonates (at frequency of ac supply) [or a statement that
fundamental frequency (or a natural frequency) of the wire is
the same as applied
How's this correct?
the ms is right. if a stationary wave vibrates with the fundamental frequency, you only see half the vibrating section. so if the length of the string is 0.4m the wavelength is 0.8m. as wavespeed = frequency x wavelength, 64/0.8 = 80Hz. resonance occurs when the natural frequency of the system = frequency of the forced vibrations.s th so as 80Hz ie natural frequency and the resonant frequency, large oscillations occur at this frequency. if you don't get this explanation you probably need to look at some of the content before you start answering questions, just some advice.