free radical substitution
why does the chlorine molecule break homolytically not the c-h bond in an alkane?
C-H bond enthalpy is nearly double that of the Cl-Cl bond enthalpy (413 vs 243 kJmol^-1). Hence UV light has enough energy to allow for homolytic fission of the Cl-Cl bond but not the C-H bond.
Quick Reply
Related discussions
- Alkanes MCQ HELP!
- A level chemistry
- Would I have lost marks for this (OCR A chem)
- Nucelophiles Vs Ligands
- chemistry question!
- A level chemistry question help.
- Radicals chemistry
- Chemistry personal statement.
- very urgent a level chem question
- Help on this free radical substitution question?
- Integration help
- Higher study tips?
- NO catalysing ozone depletion
- CIE A-levels Physics
- AS Organic Chem Practical Question
- (LOOKING FOR TENANT REPLACEMENT) Private Accommodation Cardiff (Howard Gardens)
- Software for note-taking in uni lectures (chemistry)
- Replacement tenant needed (Cardiff)
- Psychology book recommendations
- AlCl3 reacting with benzene
Latest
Trending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these productsTrending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these products
