Incline planes

It’s this right?

I had it yesterday because I got help, but forgot it because I thought what I was thinking was wrong because of your explanation but now I get it

It's always worth remembering that the original force must be the hypotenuse of the right angled triangle, so the right angle must occur between the two (perpendicular) resolved forces.

Do you understand why?

Nope, seems factual to remember though lol

Have a think/look at your examples/textbook and see if you can work out why.

It divides the components ? It balances out the force /weight

That's a start. You generally use perpendicular directions to analyse force/motion as each direction is independent of the other. As an example, motion in the horizontal direction does not interfere with the vertical direction and vice versa.
Splitting the original force into perpendicular components must mean that each component is less than the original force.
Putting the two together, in a right angled triangle, the perpendicular components must be the legs, the original force must be the hypotenuse.

So if you had a particle on an inclined plane at an 30° with weight of 20kg, since the 20g downwards is going to be more than it’s perpendicular components? Is it to do with physics? (As a further explanation)?